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Solve each of the following equations for θ, if 0^°<θ<〖360〗^°. Do not use a calculator or a table:

(a) 2sin⁡θ+√2= 0

1 Answer

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\bf 2sin(\theta)+√(2)=0\implies 2sin(\theta)=-√(2)\implies sin(\theta)=-\cfrac{√(2)}{2} \\\\\\ \measuredangle \theta=sin^(-1)\left( -\cfrac{√(2)}{2} \right)

check your Unit Circle, that's a well known angle
User Muruge
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