Question

A=1/2(B+b)h ; solve for h

Answer 1

`A=(1)/(2)(B+b)h`

First step is to divide both sides of the equation by h

`(A)/(h)=\text{ }(1)/(2)(B+b)`

Now you have to invert the equation, to do so you have to power it by -1

`\begin{gathered} ((A)/(h))^((-1))=((1)/(2)(B+b))^((-1)) \\ (h)/(A)=2((1)/(B+b)) \end{gathered}`

Now you divide both sides by A

`h=2((1)/(B+b))((1)/(A))`