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In the following balanced neutralization reaction equation, how many moles of Ca(OH)2 are required to completely neutralize 1.2 moles of HI? 2HI + Ca(OH)2 → CaI2 + 2H2O 1.2 moles 0.6 moles 2.4 moles 1.
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In the following balanced neutralization reaction equation, how many moles of Ca(OH)2 are required to completely neutralize 1.2 moles of HI? 2HI + Ca(OH)2 → CaI2 + 2H2O

1.2 moles

  0.6 moles

  2.4 moles

 1.0 mole

User JNM
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1 Answer

6 votes
0.6 because HI has a 2 in front of it so 1.2 moles is cut in half for Ca(OH)2's 1 mole

User Wildavies
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