Question

Reaction Stoichiometry

Answer 1

V= 1.8136 L

Procedure

The equation is already balanced

Mg₃N₂ + 6H₂O -> 3Mg(OH)₂ + 2NH₃

1. Use stoichiometry to get the moles of ammonia

`6.0\text{ g Mg}_3\text{N}_2\text{ }\frac{1\text{ mol Mg}_3\text{N}_2}{148.3\text{ g Mg}_3\text{N}_2}\frac{2\text{ mol NH}_3}{1\text{ mol Mg}_3\text{N}_2}=0.081\text{ mol NH}_3`

2. Use the ideal gas equation considering STP conditions to get the volume

`PV=nRT`

Solving for V

`V=(nRT)/(P)=\frac{0.081\text{ mol }0.082(\text{ L. atm. mol}^(-1)\text{. }\degree\text{K}^(-1))\text{ }273.15\degree K}{1\text{ atm}}=1.8136\text{ L}`