Final answer:
The work done by a 47 N force pushing against an opposing force of 23 N over a distance of 0.25 m is calculated as the difference in forces multiplied by the distance, resulting in 6 Joules of work.
Step-by-step explanation:
The student's question relates to the concept of work in Physics, specifically within the domain of mechanics. To calculate the work done by a force, we use the formula W = F × d × cos(θ), where W is the work done by the force, F is the magnitude of the force acting on the object, d is the distance the object moves, and θ is the angle between the force and the direction of motion. In the given scenario, if the 47 N force is acting against another force of 23 N (assumed opposing and directly along the same line), the effective force doing the work would then be (47 N - 23 N) × 0.25 m. So the work done W is calculated as:
W = (47 N - 23 N) × 0.25 mW
= 24 N × 0.25 mW
= 6 Joules
Therefore, the work done by the 47 N force over a distance of 0.25 m against a force of 23 N would be 6 Joules.