Question

The letters of the word mississippi are placed in a hat. what is the probability that the first two letters drawn are both i if the first letter drawn is not replaced?

Answer 1

For the first letter drawn, there are no conditions/restrictions we need to consider. So, the number of ways to draw an i is:

`\text{Draw(i): } (4)/(11)`

For the second draw, the i is not replaced. That means, we've shrunk the sample space because we're dealing with less elements for the second draw. Firstly, one i disappears since we picked an "i" and there are 10 elements left, not 11.

Thus, to draw the second i, we have:

`\text{Draw(ii): } (3)/(10)`


`\text{P(drawing 2 i's): } (4)/(11) \cdot (3)/(10) = (12)/(110) = (6)/(55)`