38.4k views
2 votes
A rectangle is twice as long as it is wide. The area of the rectangle is 32 square feet. Find the rectangle's width.

2 Answers

3 votes
x*y = 32
x = 2y

8 and 4. The width is 4 and the height is 8.
User Juan Zapata
by
8.3k points
1 vote

Answer: Length = 8 feet --- Width = 4 feet

Step-by-step explanation: Since the rectangle is twice as long as it is wide, we can use "X" to represent the rectangles width and "2x" to represent its length. The area of a rectangle is length × width and since the area of the rectangle is 32 and the length and width are "2x" and "X", we can set up an equation to represent this.

32 = (2x) (x)

32 = 2x²

↓ ↓

32 = 2x²

÷2 ÷2

16 = x²

If we want to get the "x" term by itself, we take the square root of both sides and we find that 4 = x. The width of the rectangle is 4 feet and the length of the rectangle is 2 (4) which equals 8 feet. Therefore, the length of the rectangle is 8 feet and the width is 4 feet.

User Asnr
by
7.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories