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A rectangular field is 4 times as long as it is wide. If the length is decreased by 10 feet and the width is increased by 2 feet, the perimeter will be 80 feet. Find the dimensions of the original field. The original dimensions are feet long by feet wide.

User Pawandeep
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2 Answers

3 votes
L = 4W [A rectangular field is 4 times as long as it is wide.]
2(L-10) + 2(W+2) = 80 [If the length is decreased by 10 feet and the width is increased by 2 feet, the perimeter will be 80 feet. ]
Distributed: (2L - 20) + (2W + 4) = 80
Substitute the known value of L from the first equation into the second.
8W - 20 + 2W + 4 = 80
10 W -16 = 80
Add 16 to each side
10W = 96

Divide each side by 10
W = 9.6 <<--original dimension
L = 9.6 * 4 = 38.4 <<--original dimension

...

If the length (38.4) is decreased by 10 feet (which would make it 28.4) and the width (9.6) is increased by 2 feet (11.6), the perimeter will be 80 feet.
28.4 + 28.4 + 11.6 + 11.6 = 80 feet.


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User Langkilde
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8.2k points
3 votes

Answer:The original dimensions are: 38.4 feet long by: 9.6 feet wide.

Explanation:

User IamOgunyinka
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