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A car traveling at 60 mph has how much more energy than a car going at 20 mph? KE increases by a factor of _____. 1/3 1/9 3 9

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Answer: 9

Step-by-step explanation:

The kinetic energy of a car is given by


E_k = (1)/(2)mv^2

where

m is the mass of the car

v is its speed

In this case, the kinetic energy of the car moving at 20 mph is


K_1 = (1)/(2)m(20)^2

While the kinetic energy of the car moving at 60 mph is (assuming same mass m)


K_2 = (1)/(2)m(60)^2

The ratio between the two kinetic energies is:


(K_2)/(K_1)=((1)/(2)m(60)^2)/((1)/(2)m(20)^2)=(60^2)/(20^2)=((60)/(20))^2=3^2=9

So, the faster car has a kinetic energy which is 9 times more than the slower car.

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