Question

What is the equation of the line perpendicular to 2x − 7y = −42 that contains the point (6, −3)?

Answer 1

Hello:
the equation is : y = ax+b
the slope is a : a×(2/7) = -1......( perpendicular to a line with a slope of 2/7) because : 2x-7y =-42...y=(2/7)x+6 )

a = -7/2 y=(-7/2)x+b
the line that passes through (6, -3) :- 3 = (-7/2)(6)+b
b =18
the equation is : y = (-7/2)x+18