In this case, we have a mutation in the 6th base, an adenine by guanine, if we go for triplets, we have the following original sequence ATG GAA GCA, coding for the following amino acids Met Glu Ala, and the mutated will be ATG GAG GCA, were the amino acid sequence is Met Glu Ala, therefore even when we have a change in the second codon still codify by the same amino acid. Therefore the correct answer is option A.