Question

Find the slope of a line perpendicular to 2x-y=16

Answer 1

The slope would be -1/2

Answer 2

Answer:
`(-1)/(2)`

Explanation:

The standard equation of a line in intercept form is given by :-

`y=mx+b`, where m is the slope of the line. (1)

Given equation of a line :
`2x-y=16`

It can be written as :

`y=2x-16`

By comparing to the equation (1) , we have

`m=2`

Also, the product of slopes of two perpendicular lines is -1.

Let p be the slope of the line perpendicular to
`2x-y=16`, then we have

`p* 2=-1\\\\\Rightarrow\ p=(-1)/(2)`

Hence, the slope of the line perpendicular to
`2x-y=16` =
`(-1)/(2)`