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What is the molarity of a solution that contains 135g of KI in 4.0 L of solution?

User Qiong Wu
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1 Answer

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Molar mass KI = 166.0028 g/mol

number of moles solute :

n = mass solute / molar mass

n = 135 / 166.0028

n = 0.813 moles

Therefore :

M = moles solute / volume

M = 0.813 / 4.0 => 0.20325 M
User SarekOfVulcan
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