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3 votes
I NEED HELP WITH #12, please explain as well! THANK YOU.

I NEED HELP WITH #12, please explain as well! THANK YOU.-example-1
User Bmeyers
by
8.1k points

2 Answers

4 votes
Hypotenuse = 4 m
Leg1 = 3 m
By Pythagorean Theorem,

(Hypotenuse)^2 = (Leg1)^2 + (Leg2)^2

4^2 = 3^2 + (Leg2)^2

16 = 9 + (Leg2)^2
16 - 9 = (Leg2)^2
7 = (Leg2)^2
sqrt(7) meters = Leg2

Answer is F
User Fazy
by
7.9k points
6 votes
By the Pythagorean Theorem:

h^2=x^2+y^2 where h is the hypotenuse and x and y are the leg lengths.

4^2=3^2+x^2

16=9+x^2

x^2=7

x=√7
User Jistr
by
8.2k points

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