Question

How to solve x2+6x+5=0 using the quadratic formula

Answer 1

So, we know, that the quadratic formula is:
x=
`\frac{-b (+)/(-) \sqrt{b^(2) -4ac} }{2a}`
If we plug in a,b and c, we get:
x=
`\frac{-6 (+)/(-) \sqrt{6^(2)-(4)(1)(5) } }{(2)(1)}`
Which would then be:
x=
`(-6 (+)/(-) √(16) )/(2)`

x=
`(-6 (+)/(-)4 )/(2)`

x=-3
`(+)/(-)`2

x=-1 and -5

So, the answers would be -1 and -5.

Answer 2

Its really easy if you think about it.. I got (x+5)(x+1)