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Someone help please!!

Someone help please!!-example-1
User Ula
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10) C) Derivative of s = √[(t³/2) +c] = 3t²/√[(t³/2) +c] ==>3t²/s

11) D) derivative of (1)/(bx+5)³ => [(-1) x 3b(bx+5)²]/(bx+5)⁶

after simplification =(-3b) / (bx+5)⁴ +c

12) y= 4x-x² intercepts x-axis at x=0 & x=4
Then we have to calculate the integral of ∫(4x-x²)dx

∫(4x-x²)dx = 2x²-x³/3 +c
Calculate the area between x = 0 & x=4
[2(4)² - (4)³/3] -[0] = 32-64/3 = 10.667 or 102/3 Answer C

User Kalpesh Fulpagare
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