Question

Patel is solving 8x2 + 16x + 3 = 0. Which steps could he use to solve the quadratic equation? Check all that apply. 8(x2 + 2x + 1) = –3 + 8 x = –1 x = –1 8(x2 + 2x + 1) = 3 + 1 8(x2 + 2x) = –3

Answer 1

abd on edge

Explanation:

i took the test

Answer 2

The steps used in solving from options are

`8(x^(2)+2x)=-3\\8(x^(2)+2x+1)=-3+8`

Explanation:

Given : Quadratic equation
`8x^2+16x+3=0`

To find : Which steps could he use to solve the quadratic equation?

Solution :

Quadratic equation
`8x^2+16x+3=0`

Step 1 - Take constant to another side,

`8x^2+16x=-3`

Step 2 - Take 8 common from LHS,

`8(x^2+2x)=-3`

Step 3 - Completing the square by adding and subtracting square of 1 inside the bracket,

`8(x^2+2x+1)=-3+8`

`8(x^2+2x+1)=5`

Step 4 - Write as perfect square,

`8(x+1)^2=5`

`(x+1)^2=(5)/(8)`

Taking root both side,

`√((x+1)^2)=\sqrt{(5)/(8)}`

`x+1=\pm 0.79`

`x_1=0.79-1=-0.21`

`x_1=-0.79-1=-1.79`

Therefore, The steps used in solving from options are

`8(x^(2)+2x)=-3\\8(x^(2)+2x+1)=-3+8`