Question

What volume of 0.10 M NaOH is required to neutralize 30 mL of 0.10 M HCl?

Answer 1

30 mL. The two compounds need to balance each other out.

Answer 2

Answer : The volume of 0.10 M NaOH required to neutralize 30 ml of 0.10 M HCl is, 30 ml.

Solution :

According to the neutralization law,

`M_1V_1=M_2V_2`

where,

`M_1` = molarity of NaOH solution = 0.10 M

`V_1` = volume of NaOH solution = ?

`M_2` = molarity of HCl solution = 0.10 M

`V_2` = volume of HCl solution = 30 ml

Now put all the given values in the above law, we get the volume of NaOH solution.

`(0.10M)* V_1=(0.10M)* (30ml)`

`V_1=30ml`

Therefore, the volume of 0.10 M NaOH required to neutralize 30 ml of 0.10 M HCl is, 30 ml.