Question

A circle has a diameter that starts

at (3, 7) and ends at (7, 3). What is the radius of the circle rounded to the nearest tenth?

Answer 1

find the distance between those points

diameter/2=radius


distance betwen (x1,y1) and (x2,y2) is

`D= √((x2-x1)^2+(y2-y1)^2)`

given
(3,7) and (7,3)


`D= √((7-3)^2+(3-7)^2)`

`D= √((4)^2+(-4)^2)`

`D= √(16+16)`

`D= √(32)`
D=4√2

diameter/2=(4√2)/2=2√2

radius is 2√2