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What are the coordinates of the turning point for the function f(x) = (x − 2)^3 + 1?

A. (−2, −1)
B. (−2, 1)
C. (2, −1)
D. (2, 1)

User Laoujin
by
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2 Answers

3 votes
The turning point is (2,1).

Hope this helps!
User Matthew Rudy
by
7.3k points
1 vote

Answer:


(2,1)

Explanation:

The given function is,


f(x) = (x -2)^3 + 1

Turning point of a graph is the point where the graph where the graph changes from increasing to decreasing (rising to falling) or decreasing to increasing (falling to rising).

For a cubic function, the critical point also serves as a turning point.


\Rightarrow f(x) = (x -2)^3 + 1


\Rightarrow f'(x) = 3(x -2)^2

For critical point,


\Rightarrow f'(x)=0


\Rightarrow 3(x -2)^2=0


\Rightarrow (x -2)^2=0


\Rightarrow x -2=0


\Rightarrow x=2

Then,
f(2) = (2 -2)^3 + 1=1

So the critical point or turning point is
(2,1)

What are the coordinates of the turning point for the function f(x) = (x − 2)^3 + 1? A-example-1
User Bgx
by
7.7k points

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