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For y=e^(xlnx) find y'(e).

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asked Jan 15, 2018 57.4k views

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For y=e^(xlnx) find y'(e).

Mathematics
college

Strigger asked

by Strigger

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y = (e^(lnx))^x
y = x^x
y' = (x)x^(x-1)
y' = (x)(x^x)/x
y' = x^x
y'(e) = e^e

Eja answered Jan 22, 2018

by Eja

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