Answer:
1.47 m
Explanation:
Given: The bedspread was 2.4 m long and made an angle of 52 degrees with the ground where it was anchored at each side.
To Find: How wide was the shady area?
Solution:
Refer the attached figure.
The bedspread was 2.4 m long i.e.AC = 2.4 m
The bedspread made an angle of 52 degrees with the ground i.e.∠ACB = 52°
Now we are supposed to find the width of shady area .i.e. BC
We will use trigonometric ratio.
In ΔABC






Hence the width of the shady area is 1.47 m