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Given: AD ≅ BC and AD ∥ BC Prove: ABCD is a parallelogram. Statements Reasons 1. AD ≅ BC; AD ∥ BC 1. given 2. ∠CAD and ∠ACB are alternate interior ∠s 2. definition of alternate interior angles 3. ∠CAD ≅ ∠ACB 3. alternate interior angles are congruent 4. AC ≅ AC 4. reflexive property 5. △CAD ≅ △ACB 5. SAS congruency theorem 6. AB ≅ CD 6. ? 7. ABCD is a parallelogram 7. parallelogram side theorem What is the missing reason in step 6?

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Given: It is given that
AD \cong BC and
AD \parallel BC.

To Prove: ABCD is a parallelogram.

Statements

1.
AD \cong BC and
AD \parallel BC

Reason: Given

2.
\angle CAD, \angle ACB are alternate interior angles

Reason: Def of alternate interior angles

3.
\angle CAD \cong \angle ACB

Reason: Alternate interior angles are congruent

4.
AC \cong AC

Reason: Reflexive property

5.
\Delta CAD \cong \Delta ACB

Reason: SAS congruency theorem

6.
AB \cong CD

Reason: Corresponding Parts of Congruent triangles are Congruent (CPCTC)

7. ABCD is a parallelogram

Reason: Parallelogram Side Theorem

User Cameron Forward
by
8.4k points
5 votes

Given: AD ≅ BC and AD ∥ BC

Prove: ABCD is a parallelogram.

Statements Reasons

1. AD ≅ BC; AD ∥ BC 1. given

2. ∠CAD and ∠ACB are alternate interior ∠s 2. definition of alternate interior angles

3. ∠CAD ≅ ∠ACB 3. alternate interior angles are congruent

4. AC ≅ AC 4. reflexive property

5. △CAD ≅ △ACB 5. SAS congruency theorem

6. AB ≅ CD 6. Corresponding Parts of Congruent triangles are Congruent (CPCTC)

7. ABCD is a parallelogram 7. parallelogram side theorem

User Bananaforscale
by
7.4k points
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