This is a geometric sequence, with the first term: 1/64
The common ratio is found through the ratio of the first two terms and the second and third term.


Since there is a common difference of 2, we can generalise this sequence to find the nth term:

a is the first term, r is the common ratio, and n is the nth term in the sequence.

Substituting n = 7, we get:



Thus, the next term in the sequence is 1.