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Give the equation of the circle centered at the origin and passing through the point (9,0).

User Georg Mavridis
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1 Answer

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24 votes

EXPLANATION

Let's see the facts:

Center of the circle---> Origin = (0,0)

Pass through point ---> (9,0)

As we can see in graph, the radius of the circle is equal to r=9

With this given information, the equation standard form will be:

(x-h)^2 + (y-k)^2 = r^2

With value of h=0 and k=0, equation will be:

x^2+y^2 = 9^2

[ANSWER] x^2 + y^2 = 81

Give the equation of the circle centered at the origin and passing through the point-example-1
User TobiasMende
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