Question

Given the following chemical reaction: 2 O2 + CH4 CO2 + 2 H2O What mass of CH4 is required to completely react with 100 grams of O2?

Answer 1

2 O2 + CH4 CO2 + 2 H2O

What mass of CH4 is required to completely react with 100 grams of O2?

mass CH4 = 100 g O2 x (1 mol O2 / 32 g) x (1 mol CH4 / 2 mol O2) x (16.05 g / 1 mol CH4)
25 grams CH4

Answer 2

Answer : The mass methane required is, 25 g

Explanation : Given,

Mass of oxygen gas = 100 g

Molar mass of oxygen gas = 32 g/mole

Molar mass of methane gas = 16 g/mole

First we have to calculate the moles of
`O_2`.

`\text{Moles of }O_2=\frac{\text{Mass of }O_2}{\text{Molar mass of }O_2}=(100g)/(32g/mole)=3.125moles`

Now we have to calculate the moles of
`CH_4`.

The balanced chemical reaction is,

`CH_4+2O_2\rightarrow CO_2+2H_2O`

From the balanced reaction we conclude that

As, 2 moles of
`O_2` react with 1 mole of
`CH_4`

So, 3.125 moles of
`O_2` react with
`(3.125)/(2)=1.563` moles of
`CH_4`

Now we have to calculate the mass of
`CH_4`

`\text{Mass of }CH_4=\text{Moles of }CH_4* \text{Molar mass of }CH_4`

`\text{Mass of }CH_4=(1.563mole)* (16g/mole)=25.008g=25g`

Therefore, the mass methane required is, 25 g