Question

A sample of gas has a volume of 2.4 L and a pressure of 1.2 atm. What would the pressure of the same gas sample be if the volume is reduced to 1.8L at a constant temperature?

Answer 1

According to Boyle's law,

PV= constant

So,2.4 X 1.2= 1.8 X P

=>. P = 1.6 atm

Answer 2

Answer: The new pressure of the gas will be 1.6 atm.

Step-by-step explanation:

To calculate the new pressure of the gas, we use the equation given by Boyle's Law. This law states that pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

Mathematically,

`P_1V_1=P_2V_2`

where,

`P_1\text{ and }V_1` are initial pressure and volume of the gas

`P_2\text{ and }V_2` are final pressure and volume of the gas

We are given:

`P_1=1.2atm\\V_1=2.4L\\P_2=?atm\\V_2=1.8L`

Putting values in above equation, we get:

`1.2atm* 2.4L=P_2* 1.8L\\\\P_2=1.6atm`

Hence, the new pressure of the gas will be 1.6 atm.