Question

if f(x)=x^2-x and g(x)=1/x and h(x) is defined with the expressions below, arrange the values of h'(1) from smallest to largest. 1) h(x)=f(x)-g(x) 2) h(x)=f(x)g(x) 3) h(x)=f(g(x))

Answer 1

f(x) = x²-x

g(x) =1/x

1) h(x) =f(x) -g(x) = (x²-x) - (1/x) = (x³-x²)/x (x≠0) =>
2)h(x) =f(x).g(x) = (x²-x).(1/x) =x(x²-1)
3)h(x) = f(g(x)) = (1/x)²-(1/x)