Question

Help, Please! I really need this done right Carlos is analyzing the results of an experiment on two groups of mice in which he compared the difference in their weight gain after feeding each group a different type of food for one month. The difference in the mean weight gain is 0.6 grams. The standard deviation of the difference in sample means is 0.305. The 68% confidence interval for the population mean difference is ±(A.0.305, B.0.600, C.0905 D.1.200) The 95% confidence interval for the population mean difference is ±(A.0.160,B.0.305,C.0.610,D.0.915)

Answer 1

The 68% confidence interval for the population mean difference is ±

0.305.

The 95% confidence interval for the population mean difference is ±

0.610.

Explanation:

Answer 2

Given:
difference in the mean weight gain is 0.60 grams
standard deviation of the difference in sample mean is 0.305

68% confidence interval for the population mean difference is a) 0.305

0.60 + 1 * 0.305
0.60 + 0.305 = 0.905
0.60 - 0.305 = 0.295

95% confidence interval for the population mean difference is c) 0.61

0.60 + 2 * 0.305
0.60 + 0.61 = 1.21
0.60 - 0.61 = -0.01