Write the expression as a single logarithm Log7X+log7Y-log7Z

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Jumpa · Answer 1 · 2018-03-07T04:55:00+0000

For this, simply use the rules of logs:

- Adding logs of the same base (which is 7 here) is the same as multiplying

-Subtracting logs of the same base is dividing
So the single log would be:

log₇(x*y/z) which is the same as

log₇(xy/z)

Write the expression as a single logarithm Log7X+log7Y-log7Z

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