52.1k views
5 votes
In the important industrial process for producing ammonia (the Haber Process), the overall reaction is: N2(g) + 3H2(g) → 2NH3(g) + 100.4 kJ A yield of NH3 of approximately 98% can be obtained at 200°C and 1,000 atmospheres of pressure. What is the ΔH in kJ of heat released per mole of NH3(g) formed?

2 Answers

3 votes

Answer:

It's also exothermic! :D

Step-by-step explanation:

User Dougkramer
by
7.8k points
5 votes
We are given the Haber Process overall reaction:

N2 (g) + 3H2 (g) ===> 2NH3 (g) H = 100.4 kJ

Yield = 98%

T = 200 C
P = 1000 atm

We need to determine the heat released per mole of NH3 formed.

solve for the number of moles produced in the process using the ideal gas equation:

PV = nRT
1000 atm * 22.4 = n * 0.0821 L atm/ mol K * (200+273) K
n = 576.82 moles * 0.98 = 565.29 moles

Therefore, the heat released per mole of NH3 is 100.4 kJ/565.29 mole NH3
ΔH = 0.1776 kJ/mole
User Stephane Maarek
by
8.5k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.