Question

A model rocket is launched with an initial upward velocity of 215/fts . The rocket's height h (in feet) after t seconds is given by the following. =h−215t16t2 Find all values of t for which the rocket's height is 97 feet

Answer 1

97 = 215t - 16t^2

16t^2 - 215t +97 = 0

Using Quadratic formula:

t = [-(-215)+- Sqrt((-215)^2-4X(16)X97)]/2X16

Solve for t:

t1 = (215+200)/32 = 12.97 seconds

t2 = (215-200)/32 = 0.46875 seconds