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How many moles of aluminum are needed to react completely with 1.2 mol of FeO? 2Al(s) + 3FeO(s) --> 3Fe(s) + Al2O3(s)
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How many moles of aluminum are needed to react completely with 1.2 mol of FeO?

2Al(s) + 3FeO(s) --> 3Fe(s) + Al2O3(s)

How many moles of aluminum are needed to react completely with 1.2 mol of FeO? 2Al-example-1
User Bug Hunter Zoro
by
7.5k points

2 Answers

7 votes
use the mole-mole ratio to solve it/

1.2 mol FeO (2 mol Al/ 3 mol FeO)= 0.80 mole FeO
User HereForLearing
by
8.8k points
0 votes

The answer to your question is

0.8mol

Hope that helped

User AyCe
by
8.2k points
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