Question

M0 Simplify V72xh y 2

Answer 1

`\bf √(72x^6y^7z)\qquad \begin{cases} 72=2\cdot 2\cdot 2\cdot 3\cdot 3\\ \qquad 2^2\cdot 2\cdot 3^2\\ x^6=x^(3\cdot 2)\\ \qquad (x^3)^2\\ y^7=y^(2+2+2+1)\\ \qquad y^2\cdot y^2\cdot y^2\cdot y^1\\ \qquad (y^3)^2\cdot y \end{cases}\\\\ -----------------------------\\\\ \sqrt[2]{2^2\cdot 2\cdot 3^2\cdot (x^3)^2\cdot (y^3)^2\cdot y\cdot z}\implies 2\cdot 3\cdot x^3\cdot y^3√(2yz) \\\\\\ 6x^3y^3√(2yz)`