first, let write down the reaction equation
2HNO3 + Na2CO3 ---> H2CO3 + 2NaNO3
find the moles of Na2CO3 in the solutions
moles= M x L---> moles Na2CO3= 0.108 M x 0.0357 L = 0.00386 mole
then do mole-mole ratio
0.00386 mol Na2CO3 ( 2 mol HNO3/ 1 mol NaCO3)= 0.00771 mol HNO3
to find concentration (molarity= mol/ Liters)
M= 0.00771 moles/ 0.025 L= 0.308 M HNO3