Question

6w^2-11w-35

I need to factor the problem

Answer 1

hello :
6w²-11w-35
Δ = b²-4ac a = 6 b= -11 c = -35
Δ = (-11)² -4(6)(-35) =121 +840 = 961=31²
w1 = (11-31)/12 = -20/12 = -5/3
w2 = (11+31)/12 =42/12 =7/2
6w²-11w-35 =6(w-w1)(w-w2) = 6(w+5/3)(w-7/2)
= 1/2(6w+10)(2w-7)

6w²-11w-35 =(3w+5)(2w-7)

Answer 2

6w^2 - 21w + 10w - 35
3w( 2w - 7) + 5 ( 2w - 7)
(3w + 5) ( 2w - 7)

This is the factorised form.