Question

If a 97 kg object is subjected to 115 N of force for 8.3 s, what is the change in velocity?

Answer 1

The change in velocity was about
`9.84~\text{m/s}`

Step-by-step explanation:

Step 1: Understand which formulas to use

The problem has the quantities: mass, force, time and change in velocity, and they are all already in their standard form/

We know that change in velocity divided by time equals to acceleration:

`a=(v-v_(0))/(t)`

Another formula that involves acceleration, mass and force is:

`F=m* a`

Step 2: Do the calculations:

The time is said to be
`8.3~\text{s}`, so the acceleration will be:

`a=(v-v_(0))/(8.3)`

Substitute this value and the value for force, mass into the other formula:

`F=m* a\\115=97* (v-v_(0))/(8.3)`

`v-v_(0)` denotes the change in velocity, so we will have to make it the subject.

`115=97* (v-v_(0))/(8.3)\\\\(115)/(97)=(v-v_(0))/(8.3)\\\\(115)/(97)* 8.3 =v-v_(0)\\\\v-v_(0)\approx 9.84`