Question

A mixture of 50% benzene and 50% toluene is contained in a cylinder at 39.36 in. hg absolute. calculate the temperature range in which a two phase system can exist.

Answer 1

The temperature range in which a two-phase system can exist in a mixture of 50% benzene and 50% toluene is between a total vapor pressure of 42.5 kPa and 42.609 kPa.

Step-by-step explanation:

To determine the temperature range in which a two-phase system can exist in a mixture of 50% benzene and 50% toluene, we need to consider the vapor pressures of the components. The vapor pressure of benzene (CH) at 50°C is 42.5 kPa and the vapor pressure of toluene (CH CH3) at the same temperature is 0.83 torr. First, we need to convert the vapor pressure of toluene to kPa, which is approximately 0.109 kPa. The total vapor pressure above the solution is the sum of the vapor pressures of the individual components, so the total vapor pressure will be 42.5 kPa + 0.109 kPa = 42.609 kPa. Therefore, a two-phase system can exist within the temperature range where the total vapor pressure above the solution is between 42.5 kPa and 42.609 kPa.

Answer 2

We are given 50% benzene and 50% toluene contained in a cylinder with a pressure of 39.36 in Hg abs. The temperature at which a two-phase system can exist will have to be established. We need to construct a T-x-y diagram at 39.36 in Hg abs as constant pressure and observe the trend of the concentration of the two compounds, from there we can see that there is an intersection between the two compounds, this is where a two-phase system exists in a particular condition, at a certain temperature.