Question

How many milliliters of 0.45 m hcl will neutralize 25.0 ml of 1.00 m koh?

Answer 1

Approx. 60⋅mL of hydrochloric acid are required.

Answer 2

55.55 mL of HCl 0.45 m are needed to neutralize 25 mL of 1 m KOH

Step-by-step explanation:

The equation that describes the reaction is:

`HCl + KOH = KCl + H_(2) O`

We can see that one mole of HCl is needed to consume one mole of KOH

Looking at the units:

`0.45 m HCl = (0.45 MOL HCl)/(Liter) \\1 m KOH = (1 MOL KOH)/(Liter)`

So, kepping in mind the previous statements, we proceed to calculate the total moles of KOH in the solution:

Now we know that we need 0.025 MOL of HCl to neutralize the solution; So:

`(0.45 MOL HCl)/(1 Liter) *(1 Liter)/(1000mLiters)=(0.00045 MOL)/(1mLiter)`

`(0.025 MOL KOH)/((0.00045 MOL HCL)/(1mLiter) ) = 55.5556 mLiters`