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If AB = 18, BC = 10, and CA = 13, list the angles of mc084-1.jpg in order from smallest to largest.

2 Answers

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The rule says that:

each small angle has a small side

then the angle in front of BC is the smallest

in front of CA is the middle

in front of AB is the largest

I hope this helped and Good luck

thank you


User Kuffs
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Answer:

Smallest: Angle A

Middle one: Angle B

Biggest: Angle C

Explanation:

You just have to use the sine rule and cosines to calculate the value of the diverse angles, it is stated that the angle that has the largest side of the triangle formed by the sides that are forming that angle would be the largest.

In this case you have that:

A

18 13

B

10 C

As you can see the Angle "A" has the smalest side opposite from it, so it is the smalest angle, then angle B has the second smallest side, so this would be the second smallest angle, and the biggest angle should be angle C since it has opposite to it the largest side.

User Tintu C Raju
by
8.3k points

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