Question

The chemical equation below shows the reaction between carbon dioxide (CO2) and lithium hydroxide (LiOH).

CO2 + 2LiOH mc011-1.jpg Li2CO3 + H2O

The molar mass CO2 is 44.01 g/mol. How many moles of LiOH are needed to react completely with 25.5 g of CO2?

Answer 1

c on edge

Step-by-step explanation:

Answer 2

`M_{CO_(2)}=44,01(g)/(mol)\\ m=25,5g\\\\ n=(m)/(M)=(25,5g)/(44,01(g)/(mol))\approx0,58mol`

CO₂ + 2LiOH ⇒ Li₂CO₃ + H₂O
1mol : 2mol
0,58mol : x


`x=(0,58mol*2mol)/(1mol)=\underline{1,16mol}`