Question

D. O3.015 m/sE. O 9.381 m/s7. An object of mass 18 kg moving with a speedof 23 m/s to the right collides with an objectof mass 17 kg moving with a speed of 16 m/sin the same direction. After collision, the 18 kg object movesto the right with a speed of 3 m/s to the right. Calculatethe velocity of the 17 kg object after collision. (1 point)A.40.894 m/sB. O 44.612 m/sC. O 26.024 m/sD.37.176 m/sAE. O 22.306 m/s

Answer 1

We are given the following information

Before collision:

Mass of the 1st object = 18 kg

Initial speed of the 1st object = 23 m/s

Mass of the 2nd object = 17 kg

Initial speed of the 2nd object = 16 m/s

After collision:

Final speed of the 1st object = 3 m/s

Final speed of the 2nd object = ?

Recall from the law of conservation of momentum, the total momentum before the collision and after the collision must be equal.

`\begin{gathered} momentum\;before=momentum\;after \\ m_1u_1+m_2u_2=m_1v_1+m_2v_2 \end{gathered}`

Let us substitute the given values and solve for the final speed of the 2nd object (v2).

`\begin{gathered} 18\cdot23+17\cdot16=18\cdot3+17\cdot v_2 \\ 686=54+17\cdot v_2 \\ 17\cdot v_2=686-54 \\ v_2=(632)/(17) \\ v_2=37.176\;\;(m)/(s) \end{gathered}`

Therefore, the velocity of the 17 kg object after the collision is 37.176 m/s

Option D is the correct answer.