Question

Find the general solution to the following differential equations. Leave your answer in implicit form.

3-t dy/dt=8

n^2- ds/dn (6s-5)^1/3=0

Answer 1

`\bf 3-t\cfrac{dy}{dt}=8\implies 3-8=t\cfrac{dy}{dt}\implies \boxed{\cfrac{-5}{t}=\cfrac{dy}{dt}}\\\\ -----------------------------\\\\ n^2-\cfrac{ds}{dn}(6s-5)^{(1)/(3)}=0\implies n^2=\cfrac{ds}{dn}(6s-5)^{(1)/(3)}\implies \boxed{\cfrac{n^2}{(6s-5)^{(1)/(3)}}=\cfrac{ds}{dn}}`

nothing to it, is just a matter of solving for the derivative, which is already there