Question

Find the correct trig ratio given for the triangle below: A 5 13 B 12 C sinA = COSA =

Answer 1

For angle A, perpendicular side is BC = 12, hypotenuse side is AC = 13 and base side is AB = 5.

Determine the trigonometric corresponding to angle A.

`\begin{gathered} \sin A=(BC)/(AC) \\ =(12)/(13) \end{gathered}`
`\cos A=(5)/(13)`
`\tan A=(12)/(5)`

For angle C, perpendicular side is AB = 5, base is BC = 12 and hypotenuse is AC =13.

Determine the trigonometric ratio corresponding to angle C.

`\begin{gathered} \sin C=(AB)/(AC) \\ =(5)/(13) \end{gathered}`
`\begin{gathered} \cos C=(BC)/(AC) \\ =(12)/(13) \end{gathered}`
`\begin{gathered} \tan C=(AB)/(BC) \\ =(5)/(12) \end{gathered}`