Question

How wide is a poster that has a length of

9/2
feet and area of
45/4
square feet?
A)
1/4 feet
B)
5/8 feet
C)
2/5 feet
D)
5/2 feet

Answer 1

D
5/2
becuase 9/2 times 5/2 is 45/4 so that is the answer

Answer 2

The correct option is D.

Explanation:

Given information:

Length of the poster =
`(9)/(2)` ft

Area of the poster =
`(45)/(4)` ft²

We need to find the width of the poster.

The area of a rectangular poster is

`A=l* w`

where, l is length and w is width.

Substitute
`A=(45)/(4)` and
`l=(9)/(2)` in the above formula.

`(45)/(4)=(9)/(2) * w`

`(45)/(4)=(9w)/(2)`

On cross multiplication we get

`45* 2=9w* 4`

`90=36w`

Divide both sides by 36.

`(90)/(36)=w`

Cancel out common factors.

`(5)/(2)=w`

The width of the poster is 5/2 ft.

Therefore the correct option is D.