Question

If the quadratic formula is used to solve 2x 2 - 3x - 1 = 0, what are the solutions?

Answer 1

(2x - 1)(x - 1) = 0
by the zero property which must be stated!!!!

2x-1=0 or x-1=0

2x=+1 or x = +1
x = 1/2


a= 2 b = -3 c= +1
+3+-√( 9 -4*2*1) / 4
+3+-√ 1/4
3+-1/4 = 1/2 or +1 as we found earlier

Answer 2

The quadratic formula used to solve a quadratic of the form ax^2+bx+c is:

x=(-b±√(b^2-4ac))/(2a) so in this case:

x=(3±√(9+8))/4

x=(3±√17)/4