Question

Divide the following polynomial 27x^2-9a/3

Answer 1

1. (6x^3+11x^2-4x-4)/(3x-2)= (2x^2 +5x +2)
2. (y^3-4y^2+7y-6)/(y-2)= (y^2 -2y +3)
3. (x^2-4)/(x-1)= (x +1) remainder: ( -3)
4. (x^3+y^3)/(x-y)= (x^2 +xy +y^2) remainder: (2y^3)
5. (x^5+y^5)/(x+y)= (x^4 -x^3y +x^2y^2 -xy^3 +y^4)
6. (16x^2-25)/(4x+5)= (4x -5)
7. (6x^2+11x-35)/(3x-5)= (2x +7)
8. (27x^5+9x^4-18x^3)/(9x^2)= (3x^3 +x^2 -2x)
11. (2a^2+a+3)/(a-1)= (2a +3) remainder: (6)

hope this helps

Answer 2

(27x^2-9a)/3
= 9x^2 - 3a

hope it helps