Question

Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule.

a(n)=1+(n-1)(-4.1)

Answer 1

1+(1−1)×(−4.1)
=1

1+(4−1)×(−4.1)
=−11.3

1+(10−1)×(−4.1)
=−35.9

Answer 2

The first term is 1

The fourth term is -11.3

The tenth term is -35.9

Explanation:

The nth term of arithmetic sequence is given by

`a_n=1+(n-1)(-4.1)`

For the first term, n = 1

`a_1=1+(1-1)(-4.1)\\a_1=1+0\\\\a_1=1`

The first term is 1

For the fourth term, n =4

`a_4=1+(4-1)(-4.1)\\a_4=1-12.3\\\\a_1=-11.3`

The fourth term is -11.3

For the tenth term, n =10

`a_(10)=1+(10-1)(-4.1)\\a_4=1-36.9\\\\a_1=-35.9`

The tenth term is -35.9