Question

Q and R are mutually exclusive events. If P(Q)=3/4 and P(R)=1/6.
Find P(Q or R)

Answer 1

Since
`Q` and
`R` are mutually exclusive, you get


`\mathbb P(Q\cup R)=\mathbb P(Q)+\mathbb P(R)=\frac34+\frac16=(11)/(12)`