Question

If the spinner shown is spun twice, what is the probability that it will land on 1 both times?

A. 1/4
B .1/2
C. 1

Answer 1

A. 1/4

Explanation:

Answer 2

`(1)/(4)`

Explanation:

When spinner is spun for the first time

Total events = {1,2,3,4,1,2,1,1} =8

Favorable events = {1,1,1,1} =4

So, probability =
`\frac{\text{Favorable outcomes }}{\text{Total outcomes}}`

So, probability of getting 1 =
`(4)/(8)`

=
`(1)/(2)`

When the spinner is spun for second time

Total events = {1,2,3,4,1,2,1,1} =8

Favorable events = {1,1,1,1} =4

So, probability =
`\frac{\text{Favorable outcomes }}{\text{Total outcomes}}`

So, probability of getting 1 =
`(4)/(8)`

=
`(1)/(2)`

So, probability that spinner will land on 1 both times :
`(1)/(2) *(1)/(2)`

=
`(1)/(4)`

Hence the probability of hat spinner will land on 1 both times is
`(1)/(4)`